SAT Math Prep

Problem:Solution:

Score Entry

Tue, 03 Nov 2026 22:26:40 GMT

Strongest: Weakest: Problem # — Topic — Why I missed it

Tue, 03 Nov 2026 22:26:40 GMT

Rounding Reference

Tue, 03 Nov 2026 22:26:40 GMT

Quick reference for rounding decimal numbers — built for SAT grid-in answers where the problem specifies "round to the nearest ___". Every digit after the decimal point has a fixed name based on its position:The shortcut The name tells you how many decimal places to keep: tenth → keep 1 decimal place hundredth → keep 2 decimal places thousandth → keep 3 decimal places Look at the digit one place to the right of where you're rounding. If it is ≥ 5 → round up (increase the last kept digit by 1) If it is < 5 → round down (keep the last kept digit as is) Copying one extra digit from the calculator "Round to the thousandth" = 3 decimal places. If your calculator shows 0.29179, the answer is 0.292 — not 0.2918. Count the decimal places before copying. Truncating instead of rounding Truncating means just cutting digits off. Rounding means checking the next digit first. Truncated to hundredths: 9.21 ✗ Rounded to hundredths: 9.22 ✓ (3rd decimal is 9 ≥ 5 → round up) Confusing "tenth" with "ten" / "hundredth" with "hundred" tenth = = 0.1 → after the decimal point (1 place) ten = 10 → before the decimal point These are completely different. The "-th" suffix always means a fraction (a small number after the decimal). Before writing any rounded answer on the SAT: Read the rounding instruction — which place name does the problem use? Translate to a count — tenth = 1, hundredth = 2, thousandth = 3 Look at the next digit — is it ≥ 5? Write the answer — count the decimal places on your screen before copying Number: 9 . 2 1 9 8 3 │ │ │ │ │ │ │ │ │ └─ hundred-thousandth (5th) │ │ │ └──── ten-thousandth (4th) │ │ └─────── thousandth (3rd) │ └────────── hundredth (2nd) └───────────── tenth (1st)

Bluebook Test 10

Mon, 09 Mar 2026 00:00:00 GMT

Date: 2026-03-09 Source: Bluebook (SAT Practice 10) Math Score: 750 / 800 Raw Score: 40/44 (91%)Strongest: PSDA (100%) — perfect again (third time: BT7, BT9, BT10) Weakest: Advanced Math Module 2 (3/5) — sign error + omitted Module 1: Perfect 22/22 — fourth consecutive perfect Module 1 (BT7, BT8, BT9, BT10) Module 2: Routed to Hard — 18/22 Notable: Sign error recurrence on Q20 (50 vs -50). Two omitted questions from time pressure.Error breakdown: 1 concept error (Q16 Geo&Trig) 1 sign error (Q20 — 50 vs -50, same pattern from BT7/BT8) 2 omitted (Q18, Q21) — time management remains the biggest issue Current: 750 ✅ Target: 730 — EXCEEDED by 20 points (second consecutive) Trajectory: 600 → 680 → 660 → 700 → 710 → 750 → 640 (OP1) → 740 (OP2) → 750 Module 1 mastered — fourth consecutive perfect score (22/22) Sign error recurrence — Q20: answered 50, correct was -50. Must check negatives on test day. Time management — 2 omitted questions (Q18, Q21). Worst omit count since BT4. PSDA perfect — 7/7, third 100% in this domain Fixing 2 omits + 1 sign error = potential ~780+

Tue, 03 Nov 2026 22:26:40 GMT

35% of Math section — 13 to 15 questions Linear Equations
Systems of Linear Equations
Linear Inequality
Graphs of Linear Systems and Inequalities Creating, solving, and interpreting linear equations and inequalities Creating, solving, and interpreting systems of linear equations Understanding and interpreting connections between algebraic and graphical representations Translate word problems into equations/inequalities Solve for variables, including when equations have no solution or infinite solutions Interpret slope and y-intercept in context Graph lines and systems, identify solutions visually Work with absolute value equations and inequalities

Graphs of Linear Systems and Inequalities

Tue, 03 Nov 2026 22:26:40 GMT

Plot the y-intercept From there, use slope to find a second point Draw the line through both points Find x-intercept: set → point Find y-intercept: set → point Draw the line through both intercepts xy¡4¡3¡2¡11234¡4¡3¡2¡11234(0;¡1)(3;1)y=23x¡1Given two visible points and : Visual clues: Steeper line = larger Flatter line = smaller Horizontal = , Vertical = undefined The solution of a system is the intersection point of the two lines.xy¡2¡112345¡2¡112345(1;2)y=x+1y=¡x+3Solution: — where the lines cross. Graph the boundary line ( version of the inequality) Choose line style: dashed (, ) or solid (, ) Shade the correct side: test a point (usually ) xy¡3¡2¡112345¡3¡2¡112345y∙¡x+2shadedregion Solid line because (boundary is included) Shaded below because Test : ✓ → is in the shaded region The solution is the overlapping shaded region (feasible region) of all inequalities.xy¡3¡2¡112345¡3¡2¡112345y>x¡1y∙¡2x+4¡53;23¢To find the intersection point of the boundary lines: "Which point is in the solution set?" — plug each answer choice into ALL inequalities; it must satisfy every one "Which graph represents the system?" — check line styles (solid/dashed), slopes, and shading direction "How many solutions does the system have?" — count intersection points visually, or compare slopes Reading solutions from graphs — the coordinates of the intersection point ARE the solution Estimating from graphs — the SAT sometimes shows a graph and asks for approximate values; read carefully from the axes Boundary cases — a point ON a dashed line is NOT in the solution set; on a solid line, it IS

Exponential Functions

Tue, 03 Nov 2026 22:26:40 GMT

→ growth → decay → constant (not exponential) To find from a table: — divide consecutive values.¡3¡2¡11232468a=1xyy=2x(growth)y=2¡x(decay)When the model is written in one unit (e.g. years) but the problem gives another (e.g. quarters), use a proportion to rewrite the exponent.Method: Example — doubling every year, rewrite in quarters (, where 4 quarters = 1 year):Sanity check: substitute one full original interval into the new exponent and verify it equals 1. Here: exponent ✓The SAT sometimes gives a wrong exponent that also passes this check. For example, also gives when — but it's wrong because it implies increases → exponent decreases, which is backwards. Always verify the direction too.No logarithms needed. Isolate the exponential term, then raise both sides to the reciprocal of the power:Example: → graph above -axis → graph below -axis (mirror image) ¡2248y=2(2)x,a>0¡22¡8¡4y=¡2(2)x,a<0¡2248y=2(2)¡x,decaya>0¡22¡8¡4y=¡2(2)¡x,decaya<0When you see an exponential function: -intercept → read directly (set ) Growth or decay? → check sign of and whether or Unit mismatch? → set up a proportion to convert the exponent before extracting any rate Solve for ? → isolate the exponential term, raise to reciprocal power — no logs needed